Question

ABC is a triangle, right angled at B. If BCDE is a square on the side BC and ACFG is a square on AC, then AD = .

• A. BE
• B. BC
• C. BF

Answer 1

The correct option is C BF

In $\Delta ACDand\Delta BCF$, we have

$\angle ACD={90}^{\circ }+\angle BCA$ and

$\angle BCF={90}^{\circ }+\angle BCA$

CF = CA (Sides of a square)

CD = CB (Sides of a square)

$\therefore \Delta DCA\cong \Delta BCF$
(by SAS congruence rule)

$\Rightarrow AD=BF$ (CPCT)