Question 2
ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.

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Solution

Given: AB = 25 cm, AC =7cm
Let BC be x cm.
In right angled triangle ACB,
$(H y p o t e n u s e)^{2} = (B a s e)^{2} + (P e r p e n d i c u l a r)^{2}$
[By Pythagoras theorem]

$\Rightarrow (A B)^{2} = (A C)^{2} + (B C)^{2} \Rightarrow (25)^{2} = (7)^{2} + x^{2} \Rightarrow 625 = 49 + x^{2} \Rightarrow x^{2} = 625 - 49 = 576 x = \sqrt{576} = 24 c m$
Thus, the length of BC is 24cm

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Similar questions

$A B C$ is a triangle right angled at $C$ . If $A B = 25 c m$ and $A C = 7 c m$ , find $B C$ .

$A B C$ is a triangle, right angles at $C$ . If $A B = 25 c m$ and $A C = 7 c m$ , find $B C$ .

△ A B C

B

B C = 7 c m, A C - A B = 1

cos A + sin A

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