ABC is a triangle, right angled at C. If $A B = 25$ cm and $A C = 7$ cm. Find BC

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Solution

Consider the given data.

$A C = 7 c m$

$A B = 25 m$
We know that Pythagoras theorem

$A B^{2} = A C^{2} + B C^{2}$

${(25)}^{2} = {(7)}^{2} + B C^{2}$

$B C^{2} = 625 - 49$

$B C^{2} = 576$

$B C = 24$ cm.

Hence, the value of $B C$ is $24$ $c m$ .

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$A B C$ is a triangle right angled at $C$ . If $A B = 25 c m$ and $A C = 7 c m$ , find $B C$ .

$A B C$ is a triangle, right angles at $C$ . If $A B = 25 c m$ and $A C = 7 c m$ , find $B C$ .

Question 2
ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.

∠ B = 90^{o}

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