Question

$ABC$ is a triangle,right angled at $C$.If $AB=25$ cm and $AC=7cm$,find $BC$.

Answer 1

Given lengths $AB=25,AC=7$
By Pythagoras theorem,
$A{B}^2=A{C}^2+B{C}^2$
Substitute $AB=25,AC=7$, we get
$(25{)}^2=(7{)}^2+B{C}^2$
$625=49+B{C}^2$
$625-49=B{C}^2$
$BC=\sqrt{576}$
$\therefore BC=24cm$