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Question

ABC is a triangle such that AB=10 and AC=3. The side BC is:

A
=7
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B
>7
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C
<7
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D
None of these
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Solution

The correct option is B >7
In ΔABC,AB=10,AC=3
In a triangle, the sum of any two sides is always greater than the third side.
(i)AB+BC>AC(ii)BC+AC>AB and
(iii)AB+AC>BC
Also, the difference of any two sides is less than the third side.
(i)BCAB<AC(ii)ACBC<AB and
(iii)(ACAB)<BC
BC>ACABBC>7 and
(10+3)>BC13>BC
BC<13

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