ABC is a triangle whose vertices are $(2, - 3), (4, 2)$ and $(- 3, 1)$ , then the centroid P is

(1, 0)

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(- 2, 1)

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(- 1, 2)

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(1, 1)

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Solution

The correct option is C $(1, 0)$
Centroid of a triangle with vertices
${(x}_{1}, y_{1}); {(x}_{2}, y_{2})$ and ${(x}_{3}, y_{3})$ is calculated by the formula $(\frac{x_{1} + x_{2} + x_{3}}{3}, \frac{y_{1} + y_{2} + y_{3}}{3})$

Hence, centroid of the given
triangle, $A B C = (\frac{2 + 4 - 3}{3}, \frac{- 3 + 2 + 1}{3}) = (1, 0)$

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