Question

ABC is a triangle with B as right angle, AC = 5 cm and AB = 4cm. A circle is drawn with O as centre and OC as radius. The length of the chord of this circle passing through C and B is

• A. 3 cm
• B. 4 cm
• C. 5 cm
• D. 6 cm

Answer 1

The correct option is A

3 cm

In right $\Delta ABC,\angle B={90}^o$

AC = 5 cm, AB = 4 cm

$\therefore B{C}^2=A{C}^2-A{B}^2$

$=5^2-4^2=25-16$

$=9=(3{)}^2$

$\therefore BC=3cm$

$\therefore$ Length of chord BC = 3 cm