Question

$ABC$ is an equilateral triangle of side $2a.$ Find each of its altitudes.

Answer 1

Since $ABC$ is an Equilateral Triangle,
Hence,
$AB=BC=AC=2a$
and
$CD=BE=AF=$ Altitudes
$\therefore$ $CD=BE=AF=\frac{\sqrt{3}}{2}\times 2a=$$\sqrt{3}a$