ABC is an equilateral triangle of side 8 cm. If DE is the segment which joining the mid-points of the side AB and BC, then the value of DE is .

4 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 4 cm
In the given figure,

AB = BC = AC = 8 cm,
DE is the segment joining the mid points of AB and BC.
According to mid point theorem,
The length of the line segment joining the mid points of any two sides of a triangle is half the length of the third side.
$∴ D E = \frac{1}{2} A C = \frac{1}{2} \times 8 = 4 c m$

Hence, the value of DE is 4 cm.

Suggest Corrections

Similar questions

The mid points of an equilateral triangle of side 10 cm are joined to form a triangle. What type of triangle is obtained by joining the mid points ?

6 c m, 7 c m

8 c m

If D, E and F are the mid points of the sides BC, CA and AB of an equilateral triangle ABC, then triangle DEF is

Join BYJU'S Learning Program