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ABC is an equ...

Question

$A B C$ is an equilateral triangle with $O$ as its center. ${\to F}_{1}, {\to F}_{2} and {\to F}_{3}$ represent three forces acting along the sides $A B, B C and A C$ respectively. If the total torque about $O$ is zero then the magnitude of ${\to F}_{3}$ is:

F_{1} - F_{2}

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\frac{F_{1} + F_{2}}{2}

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2 (F_{1} + F_{2})

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F_{1} + F_{2}

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Solution

The correct option is D $F_{1} + F_{2}$
Given:
Net torque about $O is = 0$
$(τ_{1} + τ_{2} - τ_{3}) = 0$

$\Rightarrow (F_{1} + F_{2} - F_{3}) R = 0$

$∴ F_{3} = F_{1} + F_{2}$

Hence, option $(C)$ is correct.

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The centre of an equilateral triangle is O. Three forces F1,F2 and F3 are appointed along AB, BC and AC respectively. The magnitude of F3 so that the total torque about O should be zero is

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ABC is an equilateral triangle with O as its center. →F1,→F2 and →F3 represent three forces acting along the sides AB, BC and AC respectively. If the total torque about O is zero then the magnitude of →F3 is:

The correct option is D F1+F2Given: Net torque about O is=0 (τ1+τ2−τ3)=0 ⇒ (F1+F2−F3)R=0 ∴ F3=F1+F2 Hence, option (C) is correct.

$A B C$ is an equilateral triangle with $O$ as its center. ${\to F}_{1}, {\to F}_{2} and {\to F}_{3}$ represent three forces acting along the sides $A B, B C and A C$ respectively. If the total torque about $O$ is zero then the magnitude of ${\to F}_{3}$ is:

The correct option is D $F_{1} + F_{2}$
Given:
Net torque about $O is = 0$
$(τ_{1} + τ_{2} - τ_{3}) = 0$

$\Rightarrow (F_{1} + F_{2} - F_{3}) R = 0$

$∴ F_{3} = F_{1} + F_{2}$

Hence, option $(C)$ is correct.