Question

ΔABC is an isosceles right triangle right-angled at A. If AB = 4 cm, then its area is _________.

Answer 1

Given:
ΔABC is an isosceles right triangle right-angled at A
AB = 4 cm

Since, ΔABC is an isosceles right triangle right-angled at A
Therefore, AB = AC = 4 cm

In ∆ABC,
$$\begin{gathered} \mathrm{Area}\mathrm{of}\mathrm{triangle}=\frac{1}{2}\times \mathrm{base}\times \mathrm{height} \\ =\frac{1}{2}\times AB\times AC \\ =\frac{1}{2}\times 4\times 4 \\ =8{\mathrm{cm}}^2 \end{gathered}$$


Hence, its area is $\underline{8{\mathrm{cm}}^2}$.