Question

ABC is an isosceles triangle with AB =AC and AD is one of its altitude . state the three pairs of equal parts in $\Delta ADBand\Delta ADC$

Answer 1

REF.Image

Solution :-

We have

$AB=AC$

$\Rightarrow \angle B=\angle C$

As AD is altitude, hence

$\angle ADB=\angle ADC={90}^{\circ }$

Three pairs of equal parts in $△ADB$ and $△ADC$ are

$AB=AC$

$\angle B=\angle C$

$\angle ADB=\angle ADC$

As two paris of angles in $△ADB$ and $△ADC$ are

equal, hence the third pair will also be equal

$\angle DAB=\angle DAC$