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Question
ABC is an isosceles triangle with AB=AC. P and Q are points on AB and AC respectively.
Such that AP=AQ then CP=2BQ.
ABC is an isosceles triangle with AB=AC. P and Q are points on AB and AC respectively.
Such that AP=AQ then CP=2BQ.
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Solution
The correct option is B False
Given AB=AC and AP=AQ then
From the figure PB and QC are equal acc. to your diagram
so, in ∆BQC and ∆CPB
PB=QC (proved above)
angle B = angle C(sinc AB=AC)
BC=CB( common)
∆BQC is congurnt to ∆CPB
therefore, BQ = QC (cpct)
Given AB=AC and AP=AQ then
From the figure PB and QC are equal acc. to your diagram
so, in ∆BQC and ∆CPB
PB=QC (proved above)
angle B = angle C(sinc AB=AC)
BC=CB( common)
∆BQC is congurnt to ∆CPB
therefore, BQ = QC (cpct)
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