Question

$ABC$ is right angle in which $\angle A={90}^o$ $AB=AC$. Find $\angle B$ and $\angle C$

Answer 1

In $△ABC$,
$\angle BAC=90°$
$AB=AC$
$\therefore \angle ABC=\angle ACB=x$
(Since, angles opposite to congruent sides are congruent)
In $△ABC$
$\angle A+\angle B+\angle C=180°$ (Angle sum property)
$90°+2x=180°$
$\Rightarrow x=45°$
$\therefore \angle B=\angle C=45°$