∆ABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. If ∆DEF ∼ ∆ABC and EF = 4 cm, then perimeter of ∆DEF is

(a) 7.5 cm
(b) 15 cm
(c) 22.5 cm
(d) 30 cm

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Solution

Given: In ΔABC, AB = 3cm, BC = 2cm, CA = 2.5cm. and EF = 4cm.

To find: Perimeter of ΔDEF.

We know that if two triangles are similar, then their sides are proportional

Since ΔABC and ΔDEF are similar,

From (1) and (2), we get

Perimeter of ΔDEF = DE + EF + FD = 6 + 4 +5 = 15 cm

Hence the correct answer is .

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∆ABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. If ∆DEF ∼ ∆ABC and EF = 4 cm, then perimeter of ∆DEF is (a) 7.5 cm (b) 15 cm (c) 22.5 cm (d) 30 cm

∆ABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. If ∆DEF ∼ ∆ABC and EF = 4 cm, then perimeter of ∆DEF is

(a) 7.5 cm
(b) 15 cm
(c) 22.5 cm
(d) 30 cm