∆ABC ∼ ∆PQR such that ar(∆ABC) = 4 ar(∆PQR). If BC = 12 cm, then QR =

(a) 9 cm
(b) 10 cm
(c) 6 cm
(d) 8 cm

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Solution

Given: In Δ ABC and ΔPQR

To find: Measure of QR

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

Hence the correct answer is

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