Question

$\text{(abcabc)÷(abc)=\_\_\_\_}$

where,$\text{abc}$ represents any $3$ digit number.

Answer 1

Finding $\text{(abcabc)÷(abc)=\_\_\_\_}$:

We can write $\text{abcabc}$ as $\mathrm{abc}\times 1000+\mathrm{abc}$.

Therefore,

$\begin{array}{rcl}\mathrm{abcabc}÷\mathrm{abc}& =& \frac{\mathrm{abcabc}}{\mathrm{abc}}\\ & =& \frac{\mathrm{abc}\times 1000+\mathrm{abc}}{\mathrm{abc}}\\ & =& \frac{\mathrm{abc}\times (1000+1)}{\mathrm{abc}}\\ & =& 1001\end{array}$

Hence, $\text{(abcabc)÷(abc)=1001}$.