ABCABC is a six digit number where A,B,C are three consecutive natural numbers. Find the remainder when ABCABC is divided by 1001?
1
997
cant be determined
none of these
ABCABC = ABC×1000 + ABC = ABC×1001. ∴ Remainder when ABCABC is divided by 1001 is 0.
Three consecutive natural numbers are added and their sum is divided by 3. What is the remainder obtained?