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Question

ABCD is a cyclic quadrilateral in a circle with centre O. If angleADC=130o Find BAC


  1. 120o

  2. 80o

  3. 40o

  4. 134o


Solution

The correct option is C

40o


ABCD is a cyclic quadrilateral and  ADC=130o O is the centre of the circle, AOB is the diameter.

ABC=180o130o=50o

In triangle ABC, BAC+CBA=90o

BAC+50o=90o

BAC=90o50o=40o

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