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Question

ABCD is a cyclic quadrilateral, in which DBC=80 and BAC=40. BCD (in degrees ) = ___ .

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Solution

To find, BCD = ?

Procedure : DBC = DAC

(Angles in the same segment)

DAC = 80 ......( DBC = 80)

Now, DAB = DAC + CAB

= 80 + 40 = 120

Then, DAB + BCD = 180

120 + BCD = 180

BCD = 180 - 120 = 60


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