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Question

ABCD is a cyclic quadrilateral in which:

(i) BC || AD, ∠ADC = 110° and ∠BAC = 50°. Find ∠DAC.

(ii) ∠DBC = 80° and ∠BAC = 40°. Find ∠BCD.

(iii) ∠BCD = 100° and ∠ABD = 70° find ∠ADB.

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Solution

(i) It is given that , and

We have to find

In cyclic quadrilateral ABCD

..… (1)

..… (2)

Since,

So,

Therefore in ,

So , ..… (3)

Now, ( and is transversal)

(ii) It is given that , and

We have to find

(Angle in the same segment are equal)

Hence,

(iii) It is given that, ∠BCD = 100° and ∠ABD = 70°

As we know that sum of the opposite pair of angles of cyclic quadrilateral is 180°.

DAB+BCD=180°DAB=180°-100° =80°

In ΔABD we have,

DAB+ABD+BDA=180°BDA=180°-150°=30°

Hence,


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