ABCD is a cyclic quadrilateral. Tangents at A and C intersect at P. If ∠ABC = 100∘ then what is the measure of ∠APC?
A
20∘
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B
30∘
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C
35∘
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D
40∘
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Solution
The correct option is A20∘ We know that sum of opposite angles of a cyclic quadrilateral is 180∘ ∴∠B+∠D=180∘ ⇒100+∠D=180∘ ⇒∠D=80∘ ∴∠ACP=∠PAC=80∘ In ΔPAC, ∠P+∠PAC+∠PCA.=180∘ ⇒∠P+80∘+80∘=180∘ ⇒∠P=180∘−160∘=20∘