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Question

ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If DBC=80,BAC is 40, find BCD in degrees.

  1. 60

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Solution

The correct option is A 60
Given: BAC=40 and DBC=80

BDC=BAC
[Angles formed by the same segment are equal]

BDC=40

In ΔBDC,

BDC+DBC+BCD=180
[Sum of angles in triangle]

40+80+BCD=180

BCD=180120

BCD=60

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