ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If ∠DBC=70∘ and ∠BAC=30∘, then ∠BCD= ___.
A
120∘
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B
80∘
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C
110∘
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D
100∘
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Solution
The correct option is B80∘ Given that ∠DBC=70∘ and ∠BAC=30∘. Since the angles in the same segment are equal, ∠DBC=∠DAC=70∘. Now, ∠DAC+∠CAB=∠DAB. ⟹∠DAB=30∘+70∘=100∘ Now since opposite angles are supplementary in a cyclic quadrilateral, we have ∠DAB+∠BCD=180∘. ⟹∠BCD=180∘−∠DAB=180∘−100∘=80∘