ABCD is a flower bed. If OA=21cm and OC=14m, find the area of the bed. [Use π=227]
A
161.4m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
192.5m2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
212.6m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
257.2.5m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B192.5m2 We have, OA=R=21m and OC=r=14m ∴ Area of the flower bed =Area of a quadrant of a circle of radius R - Area of a quadrant of a circle of radius r =14πR2−14πr2 =π4(R2−r2) =14×227(212−142)cm2[∴R=12m and r=14m] =(14×227×(21+14)(21−14))m2 =(14×227×35×7)m2=192.5m2