ABCD is a parallelogram and AC,BD be its diagonals Then →AC+→BD is
A
2→AB
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B
2→BC
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C
3→AB
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D
3→BC
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Solution
The correct option is A2→BC ABCD is a parallelogram so, AB||CD and AD||BC →AC=→AB+→BC (addition Theorem) →BD=→BA+→AD (addition Theorem) →AC+→BD=→AB+→BC+→BA+→AD =→AB+→BC−→AB+→BC =2→BC