Question

$ABCD$ is a parallelogram and $\angle A={60}^{\circ }$. Find the remaining angles

Answer 1

Given : $ABCD$ is a parallelogram and $\angle A={60}^{\circ }$

Solution :

We know that opposites angles of a parallelogram are equal.

Therefore,

$\angle A=\angle C={60}^{\circ }$

Also, we know that $\angle A+\angle B={180}^{\circ }$

${60}^{\circ }+\angle B={180}^{\circ }$

$\angle B={120}^{\circ }$

$\angle B=\angle D={120}^{\circ }$ (opposite angles of parallelogram)