ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (See the given figure). Then,

Δ A D B ≅ Δ C Q D

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A P = C Q

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B P = D Q

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Solution

The correct options are
B $A P = C Q$
C $B P = D Q$
As, $Δ A P B ≅ Δ C Q D$ , we obtain,
$A P = C Q (B y C P C T)$
$B P = D Q (B y C P C T)$

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ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (See the given figure). Then,

The correct options are B AP=CQ C BP=DQAs, ΔAPB≅ΔCQD, we obtain, AP=CQ(By CPCT) BP=DQ(By CPCT)

The correct options are
B $A P = C Q$
C $B P = D Q$
As, $Δ A P B ≅ Δ C Q D$ , we obtain,
$A P = C Q (B y C P C T)$
$B P = D Q (B y C P C T)$