$A B C D$ is a parallelogram and $B P C$ is a triangle with $P$ falling on $A D$ . If the area of parallelogram $A B C D = 26 c m^{2}$ , find the area of triangle $B P C$ .

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Solution

The area of $B P C$ will be $13$ $i . e .$ half of $26$
according to the theorem that the area of a triangle lying between two parallel lines of a parallelogram is having area half the parallelogram $.$

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ABCD is a parallelogram and BPC is a triangle with P falling on AD. If the area of parallelogram ABCD=26 cm2, find the area of triangle BPC.

The area of BPC will be 13 i.e. half of 26according to the theorem that the area of a triangle lying between two parallel lines of a parallelogram is having area half the parallelogram.

$A B C D$ is a parallelogram and $B P C$ is a triangle with $P$ falling on $A D$ . If the area of parallelogram $A B C D = 26 c m^{2}$ , find the area of triangle $B P C$ .

The area of $B P C$ will be $13$ $i . e .$ half of $26$
according to the theorem that the area of a triangle lying between two parallel lines of a parallelogram is having area half the parallelogram $.$