ABCD is a parallelogram and E and F are the centroids of triangles ABD and BCD respectively, then EF =
AE
In || gm ABCD, BD is joined forming two triangles ABD and BCD.
E and F are the centroid of ΔABD and ΔBCD.
Now, E and F trisect AC.
i.e., AE = EF = FC
∴EF=AE