ABCD is a parallelogram and EFGB is a rhombus. AB = 7cm; AD = 4cm. If E is the mid-point of BC, find the perimeter of the whole figure i.e., ABGFECDA.

24 cm

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30 cm

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26 cm

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28 cm

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Solution

The correct option is C
26 cm

AB = DC = 7 cm

AD = BC = 4 cm

Since E is the midpoint,

BE = EC = 2 cm

Since EFGB is a rhombus all sides are equal in length.

EF= FG = GB = 2cm

Perimeter of ABGFECDA = AB + BG + GF + FE + EC + CD + DA

= (7+ 2 + 2 + 2 + 2 + 7 + 4) cm

= 26 cm

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ABCD is a parallelogram and EFGB is a rhombus. AB = 7cm; AD = 4cm. If E is the mid-point of BC, find the perimeter of the whole figure i.e., ABGFECDA.

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