ABCD is a parallelogram and P,Q are the midpoints of DC and AB respectively. Then, area of parallelogram AQPD is equal to area of triangle ADB.

True

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False

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Solution

The correct option is A
True

Parallelogram ABCD and triangle ABD are on the same base and between same parallels .

Area( $△ A D B$ ) = $\frac{1}{2}$ Area of parallelogram(ABCD)

As P and Q are the midpoints of DC and AB, Area of parallelogram(AQPD) = $\frac{1}{2}$ Area of parallelogram(ABCD)

So, Area( $△$ ADB) = Area of parallelogram(AQPD)

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