Question

ABCD is a parallelogram and P,Q are the midpoints of DC and AB respectively. Then, area of parallelogram AQPD is equal to area of triangle ADB.

• A. True
• B. False

Answer 1

The correct option is A

True

Parallelogram ABCD and triangle ABD are on the same base and between same parallels .

Area($△ADB$) = $\frac{1}{2}$ Area of parallelogram(ABCD)

As P and Q are the midpoints of DC and AB, Area of parallelogram(AQPD) = $\frac{1}{2}$Area of parallelogram(ABCD)

So, Area($△$ADB) = Area of parallelogram(AQPD)