Question

ABCD is a parallelogram .if $\angle A={60}^{\circ }$

Find other angles

Answer 1

$\angle A={60}^{\circ }$

In parallelogram Opposite angles are equal .

So $\angle C={60}^{\circ }$

In parallelogram adjacent sides sum up to give ${180}^{\circ }$

So $\angle A+\angle D={180}^{\circ }\angle D=180-60={120}^{\circ }$

So $\angle A+\angle B={180}^{\circ }\angle B=180-60={120}^{\circ }$