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Question

ABCD is a parallelogram in which DAO=40,BAO=35 and COD=65 . Find ODC.

A
30
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B
45
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C
80
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D
90
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Solution

The correct option is C 80

AOB=COD=65 [Vertically Opposite Angles]
In ΔAOB,OAB+AOB+ABO=180
35+65+OBA=180
OBA=80
ODC=OBA=80 [Alternate interior angles as DC AB.]


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