wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

ABCD is a parallelogram in which CD is produced to P. DC = 6 cm and height BQ = 4 cm. Find the area of â–³ APB


A
6 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
24 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
48 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 12 cm2

Theorem used:
Area of triangle is half the area of parallelogram, if both are on same base and between the same parallels.


From the given figure:
ABCD ( ABCD is a parallelogram)
AB = CD = 6 cm (given)
Altitude BQ = 4 cm (given)

ABP and parallelogram ABCD are on same base and between the same parallels.

Area of ΔAPB=12×Area of ABCD

Area of ABCD=Base×Altitude

=6×4=24cm2

Area of ΔAPB=12×Area of ABCD

=12×24

Area of ΔAPB=12 cm2


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon