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Question

ABCD is a parallelogram in which CD is produced to P. DC = 6 cm and height BQ = 4 cm. Find the area of â–³ APB


A
6 cm2
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B
12 cm2
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C
24 cm2
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D
48 cm2
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Solution

The correct option is B 12 cm2

Theorem used:
Area of triangle is half the area of parallelogram, if both are on same base and between the same parallels.


From the given figure:
ABCD ( ABCD is a parallelogram)
AB = CD = 6 cm (given)
Altitude BQ = 4 cm (given)

ABP and parallelogram ABCD are on same base and between the same parallels.

Area of ΔAPB=12×Area of ABCD

Area of ABCD=Base×Altitude

=6×4=24cm2

Area of ΔAPB=12×Area of ABCD

=12×24

Area of ΔAPB=12 cm2


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