Question

ABCD is a parallelogram whose diagonals intersect at O. A line through O intersects AB at P and DC at Q. Then

• A. area (∆POA) < area (∆QOC)
• B. area (∆POA) > area (∆QOC)
• C. area (∆POA) = 2area (∆QOC)
• D. area (∆POA) = area (∆QOC)

Answer 1

The correct option is D

area (∆POA) = area (∆QOC)