Question

$ABCD$ is a parallelogram with area is $12{\text{cm}}^2$. If $BD$ is one of the diagonals of $ABCD$, find as $\left(△ABD\right)$

Answer 1

Area of parallelogram $ABCD=$ twice the area of a triangle $ABD$

$\Rightarrow$ Area of $\Delta ABD=\frac{1}{2}\times$ Area of parallelogram $ABCD$

$=\frac{1}{2}\times 12=6{cm}^2$