ABCD is a quadrilateral and let ¯¯¯¯¯¯¯¯AB=¯¯¯a,¯¯¯¯¯¯¯¯¯AD=¯¯¯b,¯¯¯¯¯¯¯¯AC=m¯¯¯a+n¯¯b. Then the area of the quadrilateral is
A
(m+n)(¯¯¯aׯ¯b)
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B
2|m+n|(¯¯¯aׯ¯b)
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C
12|m+n||¯¯¯aׯ¯b|
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D
3(m+n)|¯¯¯aׯ¯b|
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Solution
The correct option is C12|m+n||¯¯¯aׯ¯b| −−→AD=−−→AB+−−→BC+−−→CD →b−→a=−−→BD →n=−−→BD×−−→AC =(→b−→a)×(m→a+n→b) =m→b×→a−n→a×→b |→n|=(m+n)(→a×→b) Area of quadrilateral =12(m+n)|→a×→b|