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Question

ABCD is a quadrilateral and let ¯¯¯¯¯¯¯¯AB=¯¯¯a, ¯¯¯¯¯¯¯¯¯AD=¯¯¯b, ¯¯¯¯¯¯¯¯AC=m¯¯¯a+n¯¯b. Then the area of the quadrilateral is

A
(m+n)(¯¯¯aׯ¯b)
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B
2|m+n|(¯¯¯aׯ¯b)
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C
12|m+n||¯¯¯aׯ¯b|
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D
3(m+n)|¯¯¯aׯ¯b|
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Solution

The correct option is C 12|m+n||¯¯¯aׯ¯b|
AD=AB+BC+CD
ba=BD
n=BD×AC
=(ba)×(ma+nb)
=mb×ana×b
|n|=(m+n)(a×b)
Area of quadrilateral =12(m+n)|a×b|

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