MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Calculating Heights and Distances

ABCD is a qua...

Question

ABCD is a quadrilateral. Prove that cos(A+B/4)=sin(C+D/4)

Open in App

Solution

This is because

Suggest Corrections

thumbs-up

0

Similar questions

Q. In any quadrilateral

A B C D

, prove that
(i)

sin (A + B) + sin (C + D) = 0

cos (A + B) = cos (C + D)

Q. In cyclic quadrilateral

A B C D

, prove that
i .

sin (A + B) + sin (C + D) = 0

cos (A + B) = cos (C + D)

.

\frac{cos (A + B)}{cos (A - B)} = \frac{sin (C + D)}{sin (C - D)}

tan A tan B tan C + tan D = 0

Q. If three angles

A, B

C

are angles of a cyclic quadrilateral, prove that

cot B = \frac{sin A - sin C}{cos C - cos A}

If A(3,-4),B(4,5),C(5,-5),D(4,-10) are the vertices of a quadrilateral prove that ABCD is Rhombus?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Questions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Calculating Heights and Distances

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon