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ABCD is a rectangle such that CAB=60 and AC=a units
Find the area of rectangle ABCD.
  1. 32a2 

  2. 23a2

  3. 34a2
  4. 38a2


Solution

The correct option is C 34a2

In ΔABC, right-angled at B

sin 60=BCAC32=BCaBC=32a

cos 60=ABAC12=ABaAB=a2

So area of the rectangle is
=AB×BC=a2×32a=3a24

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