ABCD is a rectangle such that ∠CAB=60∘ and AC=a units. The area of rectangle ABCD is √32a2
A
True
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B
False
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Solution
The correct option is B False
In ΔABC, right-angled at B, sin60∘=BCAC⇒√32=BCa⇒BC=√32a andcos60∘=ABAC⇒12=ABa⇒AB=a2
Area of rectangle =AB×BC=a2×√32a=√3a24