ABCD is a rhombus. If its side and one diagonal measure 5 cm and 6 cm respectively, the measure of its other diagonal is
Diagonals of a rhombus bisect each other at right angle.
Let BD=6 cm⇒BE=BD2
In ΔAEB,
AB2=BE2+AE2
⇒BE2=AB2−AE2
⇒BE2=52−32
⇒BE2=25−9
⇒BE=4 cm
∵BD=2BE
∴BD=8 cm