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Question

ABCD is a rhombus. Its diagonals AC and BD intersect at the point M and satisfy BD=2AC. If the points D and M represent the complex numbers 1+i and 2i, respectively, then C represents the complex numbers

A
3i2
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B
132i
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C
1+32i
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D
3+i2
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Solution

The correct option is B 132i

Rotating DM about M by an angle 90, we have
z(2i)(1+i)(2i)=|z(2i)||(1+i)(2i)|e±iπ2
z(2i)1+2i=±i2
2z=(i2)+(42i) or (i+2)+(42i)
z=132i or 3i2

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