ABCD is a rhombus. Its diagonals AC and BD intersect at the point M & satisfy BD = 2 AC. If the points D & M represent the complex numbers 1 + i and 2 - i respectively, then A represents the complex number .................. or ...............
A
(3+12i) or (1+32i)
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B
(3−12i) or (1+32i)
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C
(3+12i) or (1−32i)
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D
(3−12i) or (1−32i)
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Solution
The correct option is C(3−12i) or (1−32i) z−(2−i)1+i−(2−i)=AMMDe2πi2 ⇒z−(2−i)−i+2i=12(±i) ⇒z=(2−i)+i2(−1+2i) z=(2i)−i2(−1+2i) ⇒z=1−32i or z=3−12i