Question

$ABCD$ is a rhombus. The length of $AB$ is $(2x+4)cm$ and the length of $CD$ is $(x+10)cm$. The perimeter of the rhombus is.

• A. $32cm$
• B. $16cm$
• C. $48cm$
• D. $64cm$

Answer 1

The correct option is D $64cm$

In a rhombus, all the sides are equal.
$\Rightarrow$ $(2x+4)cm$ = $(x+10)cm$
$\Rightarrow$ $2x-x=10-4$
$\Rightarrow$ $x$ = $6cm$
$\Rightarrow$ The side of the rhombus = $(2x+4)cm$=2(6) + 4 = 16cm
$\therefore$ The perimeter of the rhombus = $16\times 4$
= $64cm$