Question

$ABCD$ is a rhombus with $\angle ABC={56}^{\circ },$ find $\angle ACD$.

Answer 1

Consecutive angles of a rhombus are supplementary.

$\angle BCD={180}^o-\angle ABC$

$={180}^o-{56}^o$

$={124}^o$

$\therefore \angle BCD={124}^o$

Diagonals of a rhombus bisect the interior angles

$\angle ACD=\angle BCD/2$

$={124}^o/2$

$={62}^o$

$\therefore \angle ACD={62}^o$.