ABCD is a rhombus with the diagonals AC and BD intersecting at the origin on the x y plane. The equation of the straight line AD is x + y =1. What is the equation of BC? (CAT 2000)

x + y = -1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x – y = -1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + y = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A x + y = -1

Slope of line AD= -1

Hence, eqn of BC which passes through (0,-1) and (-1,0) and is parallel to x+y=1 is

(y-0)=-1(x+1)

Y=-x-1 $\Rightarrow$ x+y= -1. Option (a)

Suggest Corrections

Similar questions

4 x + y = 1

A (2, - 7)

B C

3 x - 4 y + 1 = 0

B

A B = A C

A C

ABCD is a rhombus. Find the equation of diagonal BD if A = (2, 7) and C = (6, –9).

x - y = 7

x + 4 y = 2

2 y = x, x + y = \frac{1}{3}

y = sin \frac{π x}{2}

(1, 1)

Join BYJU'S Learning Program