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Standard XII

Physics

Intro to Torque

ABCD is a squ...

Question

$A B C D$ is a square, $O$ is the center of the square. $_{1}$ , $_{2}$ , $_{3}$ and $_{4}$ represent four forces acting along sides $A B, B C, C A$ and $A D$ respectively. If torque about $O$ is zero then $|_{2} |$ is

F_{1} - F_{3} + F_{4}

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F_{1} + F_{3} + F_{4}

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F_{1} + F_{3} - F_{4}

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F_{1} - F_{3} - F_{4}

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Solution

The correct option is B- $F_{1} + F_{3} + F_{4}$
Let the perpendicular distance between force and point o is $a$
Torque = force $\times$ perpendicular distance
$τ = F_{1} . a - F_{2} . a + F_{3} . a + F_{4} . a = 0$
$F_{2} = F_{1} + F_{3} + F_{4}$

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ABCD is a square, O is the center of the square. −→F1, −→F2, −→F3 and −→F4 represent four forces acting along sides AB,BC,CA and AD respectively. If torque about O is zero then |−→F2| is

The correct option is B- F1+F3+F4Let the perpendicular distance between force and point o is aTorque = force × perpendicular distance τ=F1.a−F2.a+F3.a+F4.a=0 F2=F1+F3+F4

$A B C D$ is a square, $O$ is the center of the square. $_{1}$ , $_{2}$ , $_{3}$ and $_{4}$ represent four forces acting along sides $A B, B C, C A$ and $A D$ respectively. If torque about $O$ is zero then $|_{2} |$ is

The correct option is B- $F_{1} + F_{3} + F_{4}$
Let the perpendicular distance between force and point o is $a$
Torque = force $\times$ perpendicular distance
$τ = F_{1} . a - F_{2} . a + F_{3} . a + F_{4} . a = 0$
$F_{2} = F_{1} + F_{3} + F_{4}$