ABCD is a square- O is the point of intersection of the diagnoals of the square- Given that RS -1-4 BC and QC -1-4 DC- Find ratio of areas of shaded region -unshaded region-A- 2- 7B- 1- 8- 1- 6D- 1- 7

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Area Based Approach

ABCD is a squ...

Question

ABCD is a square. O is the point of intersection of the diagnoals of the square. Given that RS= $\frac{1}{4}$ BC and QC= $\frac{1}{4}$ DC. Find ratio of areas of shaded region : unshaded region.

1:8

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2:7

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1:6

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1:7

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Solution

The correct option is D 1:7
We can graphically divide the square into 16 equal parts as follows

The shaded region forms 2 out of the 16 parts. Hence, ratio of areas = 2:14 = 1:7

Option (d)

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ABCD is a square. O is the point of intersection of the diagnoals of the square. Given that RS= 14BC and QC= 14 DC. Find ratio of areas of shaded region : unshaded region.

The correct option is D 1:7We can graphically divide the square into 16 equal parts as follows The shaded region forms 2 out of the 16 parts. Hence, ratio of areas = 2:14 = 1:7 Option (d)

ABCD is a square. O is the point of intersection of the diagnoals of the square. Given that RS= $\frac{1}{4}$ BC and QC= $\frac{1}{4}$ DC. Find ratio of areas of shaded region : unshaded region.

The correct option is D 1:7
We can graphically divide the square into 16 equal parts as follows

The shaded region forms 2 out of the 16 parts. Hence, ratio of areas = 2:14 = 1:7

Option (d)